Traders

Alex20060503

0xd6b7180ecd2fe86a2d34c0840aa498901928e3900xd6b7…e390

Joined Jun 26, 20261 profile views

Total PnL
−$35
Realized PnL
−$35
Unrealized PnL
+$0.02
Markets traded
114

PnL Performance

No current daily PnL history for this trader. Polymarket's daily history is collected for the top 200 of the overall leaderboards, and not shown once it is more than two days old.

1D change—Total PnL
7D change—Total PnL
30D change—Total PnL
Biggest win+$4.76All time, per Polymarket
Biggest loss
Avg. trade size$1.10158 trades on Polygon

Trader intelligence

Key facts about Alex20060503's trading

  • 30 open positionsAnd 17 settled, not yet redeemed
Loading market figures
Recent win rate
—
No closed market yet
Current streak
—
Total PnL, day by day
Best placing
#632
Weather · Today · Profit & loss
Avg. trade size
$1.10
158 trades on Polygon

Market exposure & outcomes

The markets this trader traded, by category, and how the closed ones ended

Loading market figures

Top market outcomes

Loading market figures

Recent large trades

Taker trades of $1,000 or more in the last 30 days, latest first

View all
Loading large trades

Activity timeline

Newest first, times in UTC

Loading activity figures

Positions

MarketOutcomeSharesAvg. priceValueCostPnL
Will the highest temperature in San Francisco be between 64-65°F on November 15?history incompleteYes1.6959.0¢$1.08$1.00+$0.08
Will the highest temperature in Istanbul be 12°C on November 15?history incompleteYes1.7258.0¢$1.02$1.00+$0.02
Will the highest temperature in Chongqing be 15°C on November 16?history incompleteYes1.8953.0¢$1.02$1.00+$0.02
Will the highest temperature in Karachi be 33°C on November 15?history incompleteYes1.6959.0¢$1.02$1.00+$0.02
Will the highest temperature in Manila be 33°C on November 16?history incompleteYes1.9351.9¢$1.00$1.00$0.00
Will the highest temperature in Amsterdam be 10°C on November 16?history incompleteYes1.6959.0¢$0.98$1.00−$0.02

Leaderboards

LeaderboardPeriodRanked byRankShares tradedPnL
WeatherTodayProfit & loss#6320.00+$0.60